The Median Of A Triangle Divides It Into. A ABC with AD as the median BD CD 12 BC To prove. The sum of two sides of a triangle is greater than the median drawn from the vertex which is common.
Area of any triangle half the base x height. Hence option A is the correct answer. BD DC D is the mid-point of BC BDAP DC AP Multiply the both side by AP 21.
We can come up with a conjecture and say that the median of a triangle divides the triangle into two triangles with equal areas.
We can come up with a conjecture and say that the median of a triangle divides the triangle into two triangles with equal areas. Area of any triangle half the base x height. To show that this is always true we can write a short proof. Showing that the centroid divides each median into segments with a 21 ratio or that the centroid is 23 along the median.
